ID4333709

获取url里的文件扩展名

>>> import urllib.parse,os

>>> url="https://220.165.10.15/videos/v0/20140815/3d/62/77772ee94ed4c3b6d265bca9f5d576cd.f4v?key=0dcb341c18a4b6f8f246841ad03aced98&src=iqiyi.com&su=a9c60180dc324addb9501c8f4d7606d7&qyid=6ab810a4f36c4c4a96acd32d86dc52a4&client=&z=&bt=&ct=&tn=12216&uuid=b6f2e146-55f4d70e-58"

>>> os.path.splitext(urllib.parse.urlparse(url).path)[-1]

'.f4v'

>>>